2013年11月3日星期日

Le plus récent matériel de formation examen Microsoft 070-461 de certification

Si vous voulez ne se soucier plus à passer le test Microsoft 070-461, donc vous devez prendre la Q&A de Pass4Test comme le guide d'étude pendant la préparation de test Microsoft 070-461. C'est une bonne affaire parce que un petit invertissement peut vous rendre beaucoup. Utiliser la Q&A Microsoft 070-461 offerte par Pass4Test peut vous assurer à réussir le test 100%. Pass4Test a toujours une bonne réputation dans l'Industrie IT.

Aujoud'hui, c'est une société de l'informatique. Beaucoup d'organisations peut provider l'outil de se former pour le test Certification Microsoft 070-461. Mais on doit admettre que ces site n'ont pas la capacité à offrir une bonne Q&A, elles sont généralement très vagues et sans les points. C'est loin d'attirer les attentions des candidats.

Code d'Examen: 070-461
Nom d'Examen: Microsoft (Querying Microsoft SQL Server 2012)
Questions et réponses: 98 Q&As

Dans cette Industrie IT intense, le succès de test Microsoft 070-461 peut augmenter le salaire. Les gens d'obtenir le Certificat Microsoft 070-461 peuvent gagner beaucoup plus que les gens sans Certificat Microsoft 070-461. Le problème est comment on peut réussir le test plus facile?

Pass4Test, où vous pouvez trouver les conseils et les documentations de test Certification Microsoft 070-461, est un siteweb remarquable offrant les données à préparer le test IT. Les documentations partiels et les mis en nouveau sont offerts gratuitement dans le site de Pass4Test. D'ailleurs, nos experts profitent de leurs expériences et leurs efforts à lancer sans arrêts les Q&A plus proches au test réel. Vous allez passer votre examen plus facile.

Si vous voulez se prouver une compétition et s'enraciner le statut dans l'industrie IT à travers de test Certification Microsoft 070-461, c'est obligatoire que vous devez avior les connaissances professionnelles. Mais il demande pas mal de travaux à passer le test Certification Microsoft 070-461. Peut-être d'obtenir le Certificat Microsoft 070-461 peut promouvoir le tremplin vers l'Industrie IT, mais vous n'avez pas besoin de travailler autant dur à préparer le test. Vous avez un autre choix à faire toutes les choses plus facile : prendre le produit de Pass4Test comme vos matériaux avec qui vous vous pratiquez avant le test réel. La Q&A de Pass4Test est recherchée particulièrement pour le test IT.

Bien qu'Il y ait plein de talentueux dans cette société, il manque beaucoup de professionnels dans les domaine en cours de développement, l'Industrie IT est l'un de ces domaines. Donc le test Microsoft 070-461 est un bon l'examination de technique informatique. Pass4Test est un site d'offrir la formation particulière au test Microsoft 070-461.

070-461 Démo gratuit à télécharger: http://www.pass4test.fr/070-461.html

NO.1 You administer a Microsoft SQL Server 2012 database named ContosoDb. Tables are defined as shown
in the exhibit. (Click the Exhibit button.)
You need to display rows from the Orders table for the Customers row having the CustomerIdvalue set to
1 in the following XML format.
Which Transact-SQL query should you use?
A. SELECT OrderId, OrderDate, Amount, Name, Country FROM Orders
INNER JOIN Customers ON Orders.CustomerId = Customers-CustomerId
WHERE Customers.CustomerId = 1
FOR XML RAW
B. SELECT OrderId, OrderDate, Amount, Name, Country FROM Orders
INNER JOIN Customers ON Orders.CustomerId = Customers.CustomerId
WHERE Customers=CustomerId = 1
FOR XML RAW, ELEMENTS
C. SELECT OrderId, OrderDate, Amount, Name, Country FROM Orders
INNER JOIN Customers ON Orders.CustomerId = Customers.CustomerId
WHERE Customers.CustomerId = 1
FOR XML AUTO
D. SELECT OrderId, OrderDate, Amount, Name, Country FROM Orders
INNER JOIN Customers ON Orders.CustomerXd - Customers.CustomerId
WHERE Customers.CustomerId= 1
FOR XML AUTO, ELEMENTS
E. SELECT Name, Country, OrderId, OrderDate, Amount FROM Orders
INNER JOIN Customers ON Orders.CustomerId= Customers.CustomerId
WHERE Customers.CustomerId- 1
FOR XML AUTO
F. SELECT Name, Country, Crderld, OrderDate, Amount FROM Orders
INNER JOIN Customers ON Orders.CustomerId= Customers.CustomerId
WHERE Customers.CustomerId= 1
FOR XML AUTO, ELEMENTS
G. SELECT Name AS '@Name', Country AS '@Country', OrderId, OrderDate, Amount FROM Orders
INNER JOIN Customers ON Orders.CustomerId= Customers.CustomerId
WHERE Customers.CustomerId= 1
FOR XML PATH ('Customers')
H. SELECT Name AS 'Customers/Name', Country AS 'Customers/Country', OrderId, OrderDate, Amount
FROM Orders
INNER JOIN Customers ON Orders.CustomerId= Customers.CustomerId
WHERE Customers.CustomerId= 1
FOR XML PATH ('Customers')
Answer: C

Microsoft examen   certification 070-461   070-461   certification 070-461   070-461   070-461

NO.2 You administer a Microsoft SQL Server 2012 database named ContosoDb. Tables are defined as shown
in the exhibit. (Click the Exhibit button.)
You need to display rows from the Orders table for the Customers row having the CustomerId value set to
1 in the following XML format.
Which Transact-SQL query should you use?
A. SELECT OrderId, OrderDate, Amount, Name, Country FROM Orders
INNER JOIN Customers ON Orders.CustomerId = Customers-CustomerId
WHERE Customers.CustomerId = 1
FOR XML RAW
B. SELECT OrderId, OrderDate, Amount, Name, Country FROM Orders
INNER JOIN Customers ON Orders.CustomerId = Customers.CustomerId
WHERE Customers=CustomerId = 1
FOR XML RAW, ELEMENTS
C. SELECT OrderId, OrderDate, Amount, Name, Country FROM Orders
INNER JOIN Customers ON Orders.CustomerId = Customers.CustomerId
WHERE Customers.CustomerId = 1
FOR XML AUTO
D. SELECT OrderId, OrderDate, Amount, Name, Country FROM Orders
INNER JOIN Customers ON Orders.CustomerXd - Customers.CustomerId
WHERE Customers.CustomerId= 1
FOR XML AUTO, ELEMENTS
E. SELECT Name, Country, OrderId, OrderDate, Amount FROM Orders
INNER JOIN Customers ON Orders.CustomerId= Customers.CustomerId
WHERE Customers.CustomerId- 1
FOR XML AUTO
F.SELECT Name, Country, Crderld, OrderDate, Amount FROM Orders
INNER JOIN Customers ON Orders.CustomerId= Customers.CustomerId
WHERE Customers.CustomerId= 1
FOR XML AUTO, ELEMENTS
G. SELECT Name AS '@Name', Country AS '@Country', OrderId, OrderDate, Amount FROM Orders
INNER JOIN Customers ON Orders.CustomerId= Customers.CustomerId
WHERE Customers.CustomerId= 1
FOR XML PATH ('Customers')
H. SELECT Name AS 'Customers/Name', Country AS 'Customers/Country', OrderId, OrderDate, Amount
FROM Orders
INNER JOIN Customers ON Orders.CustomerId= Customers.CustomerId
WHERE Customers.CustomerId= 1
FOR XML PATH ('Customers')
Answer: D

Microsoft   070-461 examen   070-461   070-461

NO.3 You create a table that has the StudentCode, SubjectCode, and Marks columns to record mid-year
marks for students. The table has marks obtained by 50 students for various subjects.
You need to ensure that the following requirements are met:
Students must be ranked based on their average marks.
If one or more students have the same average, the same rank must be given to these students.
Consecutive ranks must be skipped when the same rank is assigned.
Which Transact-SQL query should you use?
A. SELECT StudentCode as Code,
RANK ( ) OVER (ORDER BY AVG (Marks) DESC) AS Value FROM StudentMarks
GROUP BY StudentCode
B. SELECT Id, Name, Marks, DENSE_RANK () OVER (ORDER BY Marks DESC) AS Rank FROM
StudentMarks
C. SELECT StudentCode as Code,
DENSE_RANK () OVER (ORDER BY AVG (Marks) DESC) AS Value FROM StudentMarks
GROUP BY StudentCode
D. SELECT StudentCode as Code,
NTILE (2) OVER (ORDER BY AVG (Marks) DESC) AS Value FROM StudentMarks
GROUP BY StudentCode
E. SELECT StudentCode AS Code,Marks AS Value
FROM (SELECT StudentCode, Marks AS Marks,
RANK () OVER (PARTITION BY SubjectCode ORDER BY Marks ASC) AS Rank FROM StudentMarks)
tmp WHERE Rank = 1
F. SELECT StudentCode AS Code,Marks AS Value FRCM (
SELECT StudentCode, Marks AS Marks,
RANK() OVER (PARTITION BY SubjectCode ORDER 3Y Marks DESC) AS Rank FRCM StudentMarks)
tmp WHERE Rank = 1
G. SELECT StudentCode AS Code,Marks AS Value FROM
(SELECT StudentCode, Marks AS Marks,
RANK () OVER (PARTITION BY StudentCode ORDER BY Marks ASC) AS Rank FROM StudentMarks)
tmp WHERE Rank = 1
H. SELECT StudentCode AS Code,Marks AS Value FROM
(SELECT StudentCode, Marks AS Marks,
RANXO OVER (PARTITION BY StudentCode ORDER BY Marks DESC) AS Rank FROM StudentMarks)
tmp WHERE Rank = 1
Answer: A

Microsoft   070-461 examen   070-461

NO.4 You administer a Microsoft SQL Server 2012 database named ContosoDb. Tables are defined as shown
in the exhibit. (Click the Exhibit button.)
You need to display rows from the Orders table for the Customers row having the CustomerId value set to
1 in the following XML format.
Which Transact-SQL query should you use?
A. SELECT OrderId, OrderDate, Amount, Name, Country FROM Orders
INNER JOIN Customers ON Orders.CustomerId = Customers-CustomerId
WHERE Customers.CustomerId = 1
FOR XML RAW
B. SELECT OrderId, OrderDate, Amount, Name, Country FROM Orders
INNER JOIN Customers ON Orders.CustomerId = Customers.CustomerId
WHERE Customers=CustomerId = 1
FOR XML RAW, ELEMENTS
C. SELECT OrderId, OrderDate, Amount, Name, Country FROM Orders
INNER JOIN Customers ON Orders.CustomerId = Customers.CustomerId
WHERE Customers.CustomerId = 1
FOR XML AUTO
D. SELECT OrderId, OrderDate, Amount, Name, Country FROM Orders
INNER JOIN Customers ON Orders.CustomerXd - Customers.CustomerId
WHERE Customers.CustomerId= 1
FOR XML AUTO, ELEMENTS
E. SELECT Name, Country, OrderId, OrderDate, Amount FROM Orders
INNER JOIN Customers ON Orders.CustomerId= Customers.CustomerId
WHERE Customers.CustomerId- 1
FOR XML AUTO
F.SELECT Name, Country, Crderld, OrderDate, Amount FROM Orders
INNER JOIN Customers ON Orders.CustomerId= Customers.CustomerId
WHERE Customers.CustomerId= 1
FOR XML AUTO, ELEMENTS
G. SELECT Name AS '@Name', Country AS '@Country', OrderId, OrderDate, Amount FROM Orders
INNER JOIN Customers ON Orders.CustomerId= Customers.CustomerId
WHERE Customers.CustomerId= 1
FOR XML PATH ('Customers')
H. SELECT Name AS 'Customers/Name', Country AS 'Customers/Country', OrderId, OrderDate, Amount
FROM Orders
INNER JOIN Customers ON Orders.CustomerId= Customers.CustomerId
WHERE Customers.CustomerId= 1
FOR XML PATH ('Customers')
Answer: E

Microsoft   certification 070-461   certification 070-461   certification 070-461   070-461

NO.5 You create a table that has the StudentCode, SubjectCode, and Marks columns to record mid-year
marks for students. The table has marks obtained by 50 students for various subjects.
You need to retrieve the students who scored the highest marks for each subject along with the marks.
Which Transact-SQL query should you use?
A. SELECT StudentCode as Code,
RANK ( ) OVER (ORDER BY AVG (Marks) DESC) AS Value FROM StudentMarks
GROUP BY StudentCode
B. SELECT Id, Name, Marks, DENSE_RANK () OVER (ORDER BY Marks DESC) AS Rank FROM
StudentMarks
C. SELECT StudentCode as Code,
DENSE_RANK () OVER (ORDER BY AVG (Marks) DESC) AS Value FROM StudentMarks
GROUP BY StudentCode
D. SELECT StudentCode as Code,
NTILE (2) OVER (ORDER BY AVG (Marks) DESC) AS Value FROM StudentMarks
GROUP BY StudentCode
E. SELECT StudentCode AS Code,Marks AS Value
FROM (SELECT StudentCode, Marks AS Marks,
RANK () OVER (PARTITION BY SubjectCode ORDER BY Marks ASC) AS Rank FROM StudentMarks)
tmp WHERE Rank = 1
F. SELECT StudentCode AS Code,Marks AS Value FRCM (
SELECT StudentCode, Marks AS Marks,
RANK() OVER (PARTITION BY SubjectCode ORDER 3Y Marks DESC) AS Rank FRCM StudentMarks)
tmp WHERE Rank = 1
G. SELECT StudentCode AS Code,Marks AS Value FROM
(SELECT StudentCode, Marks AS Marks,
RANK () OVER (PARTITION BY StudentCode ORDER BY Marks ASC) AS Rank FROM StudentMarks)
tmp WHERE Rank = 1
H. SELECT StudentCode AS Code,Marks AS Value FROM
(SELECT StudentCode, Marks AS Marks,
RANXO OVER (PARTITION BY StudentCode ORDER BY Marks DESC) AS Rank FROM StudentMarks)
tmp WHERE Rank = 1
Answer: F

Microsoft   070-461   070-461

NO.6 You develop a Microsoft SQL Server 2012 server database that supports an application. The application
contains a table that has the following definition:
CREATE TABLE Inventory
(ItemID int NOT NULL PRIMARY KEY,
ItemsInStore int NOT NULL,
ItemsInWarehouse int NOT NULL)
You need to create a computed column that returns the sum total of the ItemsInStore and
ItemsInWarehouse values for each row.
The new column is expected to be queried heavily, and you need to be able to index the column.
Which Transact-SQL statement should you use?
A. ALTER TABLE Inventory
All TotalItems AS Item3lnStore + ItemsInWarehouse
B. ALTER TABLE Inventory
ADD TotalItems AS ItemsInStore + ItemsInWarehouse PERSISTED
C. ALTER TABLE Inventory
ADD TotalItems AS SUM (ItemsInStore, ItemsInWarehouse) PERSISTED
D. ALTER TABLE Inventory
All TotalItems AS SUM (ItemsInStore, ItemsInWarehouse)
Answer: C

Microsoft examen   070-461   070-461

NO.7 DRAG DROP
You use a Microsoft SQL Server 2012 database.
You need to create an indexed view within the database for a report that displays Customer Name and the
total revenue for that customer.
Which four T-SQL statements should you use? (To answer, move the appropriate SQL statements from
the list of statements to the answer area and arrange them in the correct order.)
Answer:

NO.8 You develop a Microsoft SQL Server 2012 database that contains a table named Customers.
The Customers table has the following definition:
You need to create an audit record only when either the MobileNumber or HomeNumber column is
updated.
Which Transact-SQL query should you use?
A. CREATE TRIGGER TrgPhoneNumberChange
ON Customers FOR UPDATE
AS
IF COLUMNS_UPDATED (HomeNumber, MobiieNumber)
- - Create Audit Records
B. CREATE TRIGGER TrgPhoneNumberChange
ON Customers FOR UPDATE
AS
IF EXISTS( SELECT HomeNumber from inserted) OR
EXISTS (SELECT MobileNumber FROM inserted)
- - Create Audit Records
C. CREATE TRIGGER TrgPhoneNumberChange
ON Customers FOR UPDATE
AS
IF COLUMNS_CHANGED (HomeNumber, MobileNumber)
- - Create Audit Records
D. CREATE TRIGGER TrgPhoneNumberChange
ON Customers FOR UPDATE
AS
IF UPDATE (HomeNumber) OR UPDATE (MobileNumber)
- - Create Audit Records
Answer: D

Microsoft   070-461 examen   070-461

NO.9 You create a table that has the StudentCode, SubjectCode, and Marks columns to record mid-year
marks for students. The table has marks obtained by 50 students for various subjects.
You need to ensure that the top half of the students arranged by their average marks must be given a rank
of 1 and the remaining students must be given a rank of 2.
Which Transact-SQL query should you use?
A. SELECT StudentCode as Code,
RANK ( ) OVER (ORDER BY AVG (Marks) DESC) AS Value FROM StudentMarks
GROUP BY StudentCode
B. SELECT Id, Name, Marks, DENSE_RANK () OVER (ORDER BY Marks DESC) AS Rank FROM
StudentMarks
C. SELECT StudentCode as Code,
DENSE_RANK () OVER (ORDER BY AVG (Marks) DESC) AS Value FROM StudentMarks
GROUP BY StudentCode
D. SELECT StudentCode as Code,
NTILE (2) OVER (ORDER BY AVG (Marks) DESC) AS Value FROM StudentMarks
GROUP BY StudentCode
E. SELECT StudentCode AS Code,Marks AS Value
FROM (SELECT StudentCode, Marks AS Marks,
RANK () OVER (PARTITION BY SubjectCode ORDER BY Marks ASC) AS Rank FROM StudentMarks)
tmp WHERE Rank = 1
F. SELECT StudentCode AS Code,Marks AS Value FRCM (
SELECT StudentCode, Marks AS Marks,
RANK() OVER (PARTITION BY SubjectCode ORDER 3Y Marks DESC) AS Rank FRCM StudentMarks)
tmp WHERE Rank = 1
G. SELECT StudentCode AS Code,Marks AS Value FROM
(SELECT StudentCode, Marks AS Marks,
RANK () OVER (PARTITION BY StudentCode ORDER BY Marks ASC) AS Rank FROM StudentMarks)
tmp WHERE Rank = 1
H. SELECT StudentCode AS Code,Marks AS Value FROM
(SELECT StudentCode, Marks AS Marks,
RANXO OVER (PARTITION BY StudentCode ORDER BY Marks DESC) AS Rank FROM StudentMarks)
tmp WHERE Rank = 1
Answer: D

Microsoft   070-461 examen   070-461

NO.10 You administer a Microsoft SQL Server 2012 database named ContosoDb. Tables are defined as shown
in the exhibit. (Click the Exhibit button.)
You need to display rows from the Orders table for the Customers row having the CustomerId value set to
1 in the following XML format.
<row OrderId= "1" orderDate="2000-01-01T00:00:00", Amount="3400.00" Name="Customer A"
Country="Australia" />
<row OrderId="2" OrderDate="2001-01-01T00:00:00" Amount="4300.00" Name="Customer A"
Country-"Australia" />
Which Transact-SQL query should you use?
A. SELECT OrderId, OrderDate, Amount, Name, Country FROM Orders
INNER JOIN Customers ON Orders.CustomerId = Customers-CustomerId
WHERE Customers.CustomerId = 1
FOR XML RAW
B. SELECT OrderId, OrderDate, Amount, Name, Country FROM Orders
INNER JOIN Customers ON Orders.CustomerId = Customers.CustomerId
WHERE Customers=CustomerId = 1
FOR XML RAW, ELEMENTS
C. SELECT OrderId, OrderDate, Amount, Name, Country FROM Orders
INNER JOIN Customers ON Orders.CustomerId = Customers.CustomerId
WHERE Customers.CustomerId = 1
FOR XML AUTO
D. SELECT OrderId, OrderDate, Amount, Name, Country FROM Orders
INNER JOIN Customers ON Orders.CustomerId - Customers.CustomerId
WHERE Customers.CustomerId= 1
FOR XML AUTO, ELEMENTS
E. SELECT Name, Country, OrderId, OrderDate, Amount FROM Orders
INNER JOIN Customers ON Orders.CustomerId= Customers.CustomerId
WHERE Customers.CustomerId- 1
FOR XML AUTO
F. SELECT Name, Country, Crderld, OrderDate, Amount FROM Orders
INNER JOIN Customers ON Orders.CustomerId= Customers.CustomerId
WHERE Customers.CustomerId= 1
FOR XML AUTO, ELEMENTS
G. SELECT Name AS '@Name', Country AS '@Country', OrderId, OrderDate, Amount FROM Orders
INNER JOIN Customers ON Orders.CustomerId= Customers.CustomerId
WHERE Customers.CustomerId= 1
FOR XML PATH ('Customers')
H. SELECT Name AS 'Customers/Name', Country AS 'Customers/Country', OrderId, OrderDate, Amount
FROM Orders
INNER JOIN Customers ON Orders.CustomerId= Customers.CustomerId
WHERE Customers.CustomerId= 1
FOR XML PATH ('Customers')
Answer: A

Microsoft   070-461 examen   certification 070-461   070-461   certification 070-461

Pass4Test est un fournisseur professionnel des documentations à propos du test Certification IT, avec lequel vous pouvez améliorer le future de votre carrière. Vous trouverez que nos Q&As seraient persuadantes d'après d'avoir essayer nos démos gratuits. Le démo de Microsoft 070-461 (même que les autres démos) est gratuit à télécharger. Vous n'aurez pas aucune hésitation après travailler avec notre démo.

没有评论:

发表评论